What is the integral from 2 to 3 of 1/(sqrt(x-1)) ?

The integral from 2 to 3 of 1/(sqrt(x-1)) is 2sqrt(2)-2

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integral from 2 to 3 of 1/(sqrt(x-1))

\int_{2}^{3} \frac{1}{x - 1} d x

22 - 2

Decimal Notation

0.82842 \dots

Solution steps

\int_{2}^{3} \frac{1}{x - 1} d x

Apply u-substitution

: \int_{1}^{2} 2 d u

= \int_{1}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{1}^{2}

Compute the boundaries:

22 - 2

= 22 - 2

x \to - 4 lim (6 x + 11)

\frac{d}{d x} (x^{2} \cdot tan (\frac{1}{x}))

x \to 0 lim (\frac{1}{cos ( 2 x )})

\int_{0}^{L} 0 d x

x \to 3 lim (\frac{x ^{2} - 1}{x + 1})

What is the integral from 2 to 3 of 1/(sqrt(x-1)) ?
The integral from 2 to 3 of 1/(sqrt(x-1)) is 2sqrt(2)-2