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Popular >

integral of 1/(y+3)

Solution

\int \frac{1}{y + 3} d y

Solution

ln ∣ y + 3 ∣ + C

Solution steps

\int \frac{1}{y + 3} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 3

= ln ∣ y + 3 ∣

Add a constant to the solution

= ln ∣ y + 3 ∣ + C

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(3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6

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(dy)/(dt)=csc(y)

\frac{d y}{d t} = csc (y)

limit as x approaches 3 of x+1x+2

x \to 3 lim (x + 1 x + 2)

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\int x cos (58 x) d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(y+3) ?
The integral of 1/(y+3) is ln|y+3|+C