What is the solution for (3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6 ?

The solution for (3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6 is y=ln(3ln(x)+c_{1})x

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(3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6

(3 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 6

y = ln (3 ln (x) + c_{1}) x

Solution steps

(3 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (3 ln (x) + c_{1}) x

y = ln (3 ln (x) + c_{1}) x

\frac{d y}{d t} = csc (y)

x \to 3 lim (x + 1 x + 2)

\int x cos (58 x) d x

\int \frac{1}{x ^{2} - 4 x + 40} d x

\frac{\partial}{\partial x} (cos^{3} (1 - 5 x^{2}))

What is the solution for (3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6 ?
The solution for (3x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=6 is y=ln(3ln(x)+c_{1})x