What is the derivative of (7x+8(8x-9)) ?

The derivative of (7x+8(8x-9)) is 112x+1

What is the first derivative of (7x+8(8x-9)) ?

The first derivative of (7x+8(8x-9)) is 112x+1

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\frac{d}{d x} ((7 x + 8) (8 x - 9))

112 x + 1

Solution steps

\frac{d}{d x} ((7 x + 8) (8 x - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 7 x + 8, g = 8 x - 9

= \frac{d}{d x} (7 x + 8) (8 x - 9) + \frac{d}{d x} (8 x - 9) (7 x + 8)

\frac{d}{d x} (7 x + 8) = 7

\frac{d}{d x} (8 x - 9) = 8

= 7 (8 x - 9) + 8 (7 x + 8)

Simplify

7 (8 x - 9) + 8 (7 x + 8) : 112 x + 1

= 112 x + 1

\int \frac{x ^{2} - 225}{x} d x

y^{^{'}} = 2 x 1 - y^{2}

\frac{d}{d x} ((A x + B) e^{x})

y^{^{'}} + y = e^{9 t}, y (0) = - 1

x \to 2 lim (\frac{x + 3}{x + 2})

What is the derivative of (7x+8(8x-9)) ?
The derivative of (7x+8(8x-9)) is 112x+1
What is the first derivative of (7x+8(8x-9)) ?
The first derivative of (7x+8(8x-9)) is 112x+1