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Popular >

y^'=2xsqrt(1-y^2)

Solution

y^{^{'}} = 2 x 1 - y^{2}

Solution

y = sin (x^{2} + c_{1})

Solution steps

y^{'} (x) = 2 x 1 - y^{2}

Solve separable ODE:

y = sin (x^{2} + c_{1})

y = sin (x^{2} + c_{1})

Popular Examples

derivative of (Ax+Be^x)

\frac{d}{d x} ((A x + B) e^{x})

y^'+y=e^{9t},y(0)=-1

y^{^{'}} + y = e^{9 t}, y (0) = - 1

limit as x approaches 2 of (x+3)/(x+2)

x \to 2 lim (\frac{x + 3}{x + 2})

(\partial)/(\partial y)(xy^3+4ye^x-2y^2)

\frac{\partial}{\partial y} (x y^{3} + 4 y e^{x} - 2 y^{2})

(\partial)/(\partial y)(ln((y/x)^2))

\frac{\partial}{\partial y} (ln ((\frac{y}{x})^{2}))

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xsqrt(1-y^2) ?
The solution for y^'=2xsqrt(1-y^2) is y=sin(x^2+c_{1})