What is the limit as θ approaches 0 of (sin(7θ))/θ ?

The limit as θ approaches 0 of (sin(7θ))/θ is 7

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limit as θ approaches 0 of (sin(7θ))/θ

θ \to 0 lim (\frac{sin ( 7 θ )}{θ})

7

Solution steps

θ \to 0 lim (\frac{sin ( 7 θ )}{θ})

Apply L'Hopital's Rule

: θ \to 0 lim (\frac{cos ( 7 θ ) \cdot 7}{1})

= θ \to 0 lim (\frac{cos ( 7 θ ) \cdot 7}{1})

Plug in the value

θ = 0

= \frac{cos ( 7 \cdot 0 ) \cdot 7}{1}

Simplify

\frac{cos ( 7 \cdot 0 ) \cdot 7}{1} : 7

= 7

x^{2} - 5 x + 9

y = arccos (4 x^{4})

\frac{\partial}{\partial x} (\frac{x}{x ^{2} - 2 x + 1})

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

(- 2, 5.5), (0, 5.5)

What is the limit as θ approaches 0 of (sin(7θ))/θ ?
The limit as θ approaches 0 of (sin(7θ))/θ is 7