What is the derivative of x^2-5x+9 ?

The derivative of x^2-5x+9 is 2x-5

What is the first derivative of x^2-5x+9 ?

The first derivative of x^2-5x+9 is 2x-5

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derivative of

x^{2} - 5 x + 9

2 x - 5

Solution steps

\frac{d}{d x} (x^{2} - 5 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (9) = 0

= 2 x - 5 + 0

Simplify

= 2 x - 5

y = arccos (4 x^{4})

\frac{\partial}{\partial x} (\frac{x}{x ^{2} - 2 x + 1})

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

(- 2, 5.5), (0, 5.5)

\int \frac{5 x ^{2} + x - 34}{( x + 1 ) ^{2} ( x - 4 )} d x

What is the derivative of x^2-5x+9 ?
The derivative of x^2-5x+9 is 2x-5
What is the first derivative of x^2-5x+9 ?
The first derivative of x^2-5x+9 is 2x-5