What is inverse oflaplace (-60)/(-2+5s) ?

The answer to inverse oflaplace (-60)/(-2+5s) is -12e^{(2t)/5}

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inverse oflaplace (-60)/(-2+5s)

inverse laplace

\frac{- 60}{- 2 + 5 s}

- 12 e^{\frac{2 t}{5}}

Solution steps

L^{- 1} {\frac{- 60}{- 2 + 5 s}}

= L^{- 1} {- 12 \cdot \frac{1}{s - \frac{2}{5}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - 12 L^{- 1} {\frac{1}{s - \frac{2}{5}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - \frac{2}{5}}} = e^{\frac{2 t}{5}}

= - 12 e^{\frac{2 t}{5}}

(\frac{e ^{x} + e ^{- x}}{2})^{^{'}}

y = x^{\frac{1}{3}}

t \to 1 lim (ln (t - 1))

\frac{d}{d x} ((\frac{x ^{2}}{4} + 5 x - \frac{1}{x})^{3})

\frac{( 3 s + 5 )}{2 s ^{2} + 6 s + 4}

What is inverse oflaplace (-60)/(-2+5s) ?
The answer to inverse oflaplace (-60)/(-2+5s) is -12e^{(2t)/5}