What is inverse oflaplace 3/s+(24)/(s^2) ?

The answer to inverse oflaplace 3/s+(24)/(s^2) is 3\H(t)+24t

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inverse oflaplace 3/s+(24)/(s^2)

inverse laplace

\frac{3}{s} + \frac{24}{s ^{2}}

3 H (t) + 24 t

Solution steps

L^{- 1} {\frac{3}{s} + \frac{24}{s ^{2}}}

Use the linearity property of Inverse Laplace Transform:

For functions

f (s), g (s)

and constants

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= L^{- 1} {\frac{3}{s}} + L^{- 1} {\frac{24}{s ^{2}}}

L^{- 1} {\frac{3}{s}} : 3 H (t)

L^{- 1} {\frac{24}{s ^{2}}} : 24 t

= 3 H (t) + 24 t

\frac{d ^{2} y}{d x} + 4 \frac{d y}{d x} - 12 y = 0

\frac{\partial}{\partial x} (x sin (8 x^{2} y))

\frac{- 60}{- 2 + 5 s}

(\frac{e ^{x} + e ^{- x}}{2})^{^{'}}

y = x^{\frac{1}{3}}

What is inverse oflaplace 3/s+(24)/(s^2) ?
The answer to inverse oflaplace 3/s+(24)/(s^2) is 3\H(t)+24t