What is the tangent of f(x)=4x+6sqrt(x),\at x=4 ?

The tangent of f(x)=4x+6sqrt(x),\at x=4 is y= 11/2 x+6

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tangent of f(x)=4x+6sqrt(x),\at x=4

tangent of

f (x) = 4 x + 6 x, at x = 4

y = \frac{11}{2} x + 6

Solution steps

Find the tangent point:

(4, 28)

Find the slope of

f (x) = 4 x + 6 x : \frac{df ( x )}{d x} = 4 + \frac{3}{x}

Compute the slope of

f (x) = 4 x + 6 x

x = 4 : m = \frac{11}{2}

Find the line with slope m=

\frac{11}{2}

and passing through

(4, 28) : y = \frac{11}{2} x + 6

y = \frac{11}{2} x + 6

f (x) = - 3 - 4 x^{2}, (5, - 103)

f (x) = 2 x^{3} - x^{2} + 1, at x = 2

sin (x) - cos (x)

x \frac{d y}{d x} + y = x^{4} ln (x)

x \to 2 + lim (\frac{x + 2}{x ^{2} - 4})

What is the tangent of f(x)=4x+6sqrt(x),\at x=4 ?
The tangent of f(x)=4x+6sqrt(x),\at x=4 is y= 11/2 x+6