What is the solution for x(dy)/(dx)+y=x^4ln(x) ?

The solution for x(dy)/(dx)+y=x^4ln(x) is y=(x^4ln(x))/5-(x^4}{25}+\frac{c_{1})/x

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x(dy)/(dx)+y=x^4ln(x)

x \frac{d y}{d x} + y = x^{4} ln (x)

y = \frac{x ^{4} ln ( x )}{5} - \frac{x ^{4}}{25} + \frac{c _{1}}{x}

Solution steps

x \frac{d y}{d x} + y = x^{4} ln (x)

Solve linear ODE:

y = \frac{x ^{4} ln ( x )}{5} - \frac{x ^{4}}{25} + \frac{c _{1}}{x}

y = \frac{x ^{4} ln ( x )}{5} - \frac{x ^{4}}{25} + \frac{c _{1}}{x}

x \to 2 + lim (\frac{x + 2}{x ^{2} - 4})

5 + 2 x

\int \frac{1}{x ^{2} 7 - x ^{2}} d x

\frac{\partial}{\partial t} (\frac{( s - r )}{t})

x \to 10 lim (\frac{( 3 x ^{2} - 30 x )}{x ^{2} - 100})

What is the solution for x(dy)/(dx)+y=x^4ln(x) ?
The solution for x(dy)/(dx)+y=x^4ln(x) is y=(x^4ln(x))/5-(x^4}{25}+\frac{c_{1})/x