What is the derivative of 8/(ln(x)) ?

The derivative of 8/(ln(x)) is -8/(xln^2(x))

What is the first derivative of 8/(ln(x)) ?

The first derivative of 8/(ln(x)) is -8/(xln^2(x))

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derivative of

\frac{8}{ln ( x )}

- \frac{8}{x ln ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{8}{ln ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{ln ( x )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (ln^{- 1} (x))

Apply the chain rule:

- \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

= - \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 8 (- \frac{1}{( ln ( x ) ) ^{2}} \cdot \frac{1}{x})

Simplify

8 (- \frac{1}{ln ^{2} ( x )} \cdot \frac{1}{x}) : - \frac{8}{x ln ^{2} ( x )}

= - \frac{8}{x ln ^{2} ( x )}

sec^{2} (x)

\int \frac{cos ( 8 x )}{cos ^{2} ( 4 x )} d x

\int 1 + sin^{2} (x) d x

\int \frac{1}{9 - x} d x

\int sin (\frac{3 x}{2}) d x

What is the derivative of 8/(ln(x)) ?
The derivative of 8/(ln(x)) is -8/(xln^2(x))
What is the first derivative of 8/(ln(x)) ?
The first derivative of 8/(ln(x)) is -8/(xln^2(x))