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Popular >

(dy)/(dx)=x^2+y-1

Solution

\frac{d y}{d x} = x^{2} + y - 1

Solution

y = - x^{2} - 2 x - 1 + c_{1} e^{x}

Solution steps

\frac{d y}{d x} = x^{2} + y - 1

Solve linear ODE:

y = - x^{2} - 2 x - 1 + c_{1} e^{x}

y = - x^{2} - 2 x - 1 + c_{1} e^{x}

Popular Examples

y^{''}+9y=2sin(2x),y(0)=0,y^'(0)=-1

y^{^{''}} + 9 y = 2 sin (2 x), y (0) = 0, y^{^{'}} (0) = - 1

tangent of (4x)/((x^2+1))tangent of

\frac{4 x}{( x ^{2} + 1 )}

integral from 0 to 3 of (1+6x^2-10x^4)

\int_{0}^{3} (1 + 6 x^{2} - 10 x^{4}) d x

maclaurin (1+px)^{-1}maclaurin

(1 + p x)^{- 1}

derivative of 8/(ln(x))derivative of

\frac{8}{ln ( x )}

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dx)=x^2+y-1 ?
The solution for (dy)/(dx)=x^2+y-1 is y=-x^2-2x-1+c_{1}e^x