What is the solution for (dx)/(dt)+x^2=x ?

The solution for (dx)/(dt)+x^2=x is x=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}

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(dx)/(dt)+x^2=x

\frac{d x}{d t} + x^{2} = x

x = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Solution steps

\frac{d x}{d t} + x^{2} = x

Solve separable ODE:

x = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

x = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

\frac{\partial}{\partial y} (ln (x + 2 y))

f (x) = ln^{2} (x)

\frac{4}{1 + x}

\frac{d}{d x} (sin (2 x^{4}))

\frac{d}{d x} (\frac{1}{- sin ( x )})

What is the solution for (dx)/(dt)+x^2=x ?
The solution for (dx)/(dt)+x^2=x is x=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}