What is the derivative of f(x)=ln^2(x) ?

The derivative of f(x)=ln^2(x) is (2ln(x))/x

What is the first derivative of f(x)=ln^2(x) ?

The first derivative of f(x)=ln^2(x) is (2ln(x))/x

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derivative of

f (x) = ln^{2} (x)

\frac{2 ln ( x )}{x}

Solution steps

\frac{d}{d x} (ln^{2} (x))

Apply the chain rule:

2 ln (x) \frac{d}{d x} (ln (x))

= 2 ln (x) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

\frac{4}{1 + x}

\frac{d}{d x} (sin (2 x^{4}))

\frac{d}{d x} (\frac{1}{- sin ( x )})

\int ((1 - (\frac{x ^{2}}{9})))^{\frac{1}{2}} d x

What is the derivative of f(x)=ln^2(x) ?
The derivative of f(x)=ln^2(x) is (2ln(x))/x
What is the first derivative of f(x)=ln^2(x) ?
The first derivative of f(x)=ln^2(x) is (2ln(x))/x