What is the derivative of (sqrt(x)/(x+1)) ?

The derivative of (sqrt(x)/(x+1)) is (-x+1)/(2sqrt(x)(x+1)^2)

What is the first derivative of (sqrt(x)/(x+1)) ?

The first derivative of (sqrt(x)/(x+1)) is (-x+1)/(2sqrt(x)(x+1)^2)

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\frac{d}{d x} (\frac{x}{x + 1})

\frac{- x + 1}{2 x ( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (x + 1) = 1

= \frac{\frac{1}{2 x} ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

= \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

\int 8 sin^{2} (x - \frac{π}{12}) d x

\frac{d y}{d x} = \frac{( 2 x y - x y ^{2} )}{x ^{2}}

\frac{\partial}{\partial y} (\frac{x y}{x + y})

f (t) = \frac{3}{t}

\frac{d}{d x} (- \frac{3}{4} e^{- \frac{x}{4}})

What is the derivative of (sqrt(x)/(x+1)) ?
The derivative of (sqrt(x)/(x+1)) is (-x+1)/(2sqrt(x)(x+1)^2)
What is the first derivative of (sqrt(x)/(x+1)) ?
The first derivative of (sqrt(x)/(x+1)) is (-x+1)/(2sqrt(x)(x+1)^2)