What is (\partial)/(\partial y)(x-y-1) ?

The answer to (\partial)/(\partial y)(x-y-1) is -1

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(\partial)/(\partial y)(x-y-1)

\frac{\partial}{\partial y} (x - y - 1)

- 1

Solution steps

\frac{\partial}{\partial y} (x - y - 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (1) = 0

= 0 - 1 - 0

Simplify

= - 1

x \to 0 lim (e^{- x} cos (x))

\frac{d ^{2}}{d x ^{2}} (sec (x))

e^{e^{x}} \to 0 + lim (\frac{e ^{e^{x} - 2}}{e ^{e^{x}}})

(x - 1) (x^{2} - 8 x + 7)

\frac{d}{d x} (sin^{2} (x) + x)

What is (\partial)/(\partial y)(x-y-1) ?
The answer to (\partial)/(\partial y)(x-y-1) is -1