What is the derivative of sin^2(x+x) ?

The derivative of sin^2(x+x) is sin(2x)+1

What is the first derivative of sin^2(x+x) ?

The first derivative of sin^2(x+x) is sin(2x)+1

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\frac{d}{d x} (sin^{2} (x) + x)

sin (2 x) + 1

Solution steps

\frac{d}{d x} (sin^{2} (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin^{2} (x)) + \frac{d x}{d x}

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

\frac{d x}{d x} = 1

= sin (2 x) + 1

\frac{d}{d x} (5 x^{3} cos (x))

\frac{\partial}{\partial x} (y x)

\frac{\partial}{\partial x} (3 y)

\int \frac{9}{x} d x

\frac{d}{d x} (x ln (2))

What is the derivative of sin^2(x+x) ?
The derivative of sin^2(x+x) is sin(2x)+1
What is the first derivative of sin^2(x+x) ?
The first derivative of sin^2(x+x) is sin(2x)+1