What is the derivative of ((4+h)^2-16)/h ?

The derivative of ((4+h)^2-16)/h is 1

What is the first derivative of ((4+h)^2-16)/h ?

The first derivative of ((4+h)^2-16)/h is 1

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derivative of

\frac{( 4 + h ) ^{2} - 16}{h}

1

Solution steps

\frac{d}{d h} (\frac{( 4 + h ) ^{2} - 16}{h})

Simplify

\frac{( 4 + h ) ^{2} - 16}{h} : h + 8

= \frac{d}{d h} (h + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d h}{d h} + \frac{d}{d h} (8)

\frac{d h}{d h} = 1

\frac{d}{d h} (8) = 0

= 1 + 0

Simplify

= 1

h \to 0 lim (\frac{1 - cos ( 2 h )}{h})

x e^{- x + 1}, 1

x^{x} (ln (x) + 1)

\int \frac{1}{x ^{3} x ^{2} - 1} d x

4 cos^{2} (x)

What is the derivative of ((4+h)^2-16)/h ?
The derivative of ((4+h)^2-16)/h is 1
What is the first derivative of ((4+h)^2-16)/h ?
The first derivative of ((4+h)^2-16)/h is 1