What is the limit as h approaches 0 of (1-cos(2h))/h ?

The limit as h approaches 0 of (1-cos(2h))/h is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as h approaches 0 of (1-cos(2h))/h

h \to 0 lim (\frac{1 - cos ( 2 h )}{h})

0

Solution steps

h \to 0 lim (\frac{1 - cos ( 2 h )}{h})

Apply L'Hopital's Rule

= h \to 0 lim (\frac{2 sin ( 2 h )}{1})

Plug in the value

h = 0

= \frac{2 sin ( 2 \cdot 0 )}{1}

Simplify

\frac{2 sin ( 2 \cdot 0 )}{1} : 0

= 0

What is the limit as h approaches 0 of (1-cos(2h))/h ?
The limit as h approaches 0 of (1-cos(2h))/h is 0