What is the solution for (dy)/(dt)-26t^{12}e^{-y}=0 ?

The solution for (dy)/(dt)-26t^{12}e^{-y}=0 is y=ln(2t^{13}+c_{1})

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(dy)/(dt)-26t^{12}e^{-y}=0

\frac{d y}{d t} - 26 t^{12} e^{- y} = 0

y = ln (2 t^{13} + c_{1})

Solution steps

\frac{d y}{d t} - 26 t^{12} e^{- y} = 0

Solve separable ODE:

y = ln (2 t^{13} + c_{1})

y = ln (2 t^{13} + c_{1})

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What is the solution for (dy)/(dt)-26t^{12}e^{-y}=0 ?
The solution for (dy)/(dt)-26t^{12}e^{-y}=0 is y=ln(2t^{13}+c_{1})