What is the tangent of f(x)=(4x)/(x^2+1),(1,2) ?

The tangent of f(x)=(4x)/(x^2+1),(1,2) is y=2

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tangent of f(x)=(4x)/(x^2+1),(1,2)

tangent of

f (x) = \frac{4 x}{x ^{2} + 1}, (1, 2)

y = 2

Solution steps

Find the slope of

f (x) = \frac{4 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x}{x ^{2} + 1}

(1, 2) : m = 0

Find the line with slope m=

0

and passing through

(1, 2) : y = 2

y = 2

4 e^{\frac{t}{2}}

\int \frac{1}{36 - x ^{2}} d x

\int sin^{3} (6 x) cos^{- 2} (6 x) d x

\int \frac{I n x}{x} d x

y^{^{''}} + 9 y^{^{'}} + 8 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the tangent of f(x)=(4x)/(x^2+1),(1,2) ?
The tangent of f(x)=(4x)/(x^2+1),(1,2) is y=2