What is the integral of 4\sqrt[3]{x} ?

The integral of 4\sqrt[3]{x} is 3x^{4/3}+C

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integral of 4\sqrt[3]{x}

3 x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 4 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

4 \cdot \frac{3}{4} x^{\frac{4}{3}} : 3 x^{\frac{4}{3}}

= 3 x^{\frac{4}{3}}

Add a constant to the solution

= 3 x^{\frac{4}{3}} + C

z \to (1 - i) lim (x + i (2 x + y))

\frac{x}{x ^{2} + 16}

y = sin (x^{2})

\int \frac{- 6}{x ^{2} + 16} d x

x \to 1 + lim (\frac{2}{1 - x})

What is the integral of 4\sqrt[3]{x} ?
The integral of 4\sqrt[3]{x} is 3x^{4/3}+C