What is the integral of 1/((x+a)^2) ?

The integral of 1/((x+a)^2) is -1/(x+a)+C

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integral of 1/((x+a)^2)

\int \frac{1}{( x + a ) ^{2}} d x

- \frac{1}{x + a} + C

Solution steps

\int \frac{1}{( x + a ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = x + a

= - \frac{1}{x + a}

Add a constant to the solution

= - \frac{1}{x + a} + C

\int sin (a x) sin (b x) d x

y = x^{4} + 5 e^{x}, (0, 5)

\frac{\partial}{\partial x} (2 x e^{8 x y})

x \to 0 lim (\frac{9 ^{x} - 1 0 ^{x}}{x})