What is the derivative of 1/(2x-8/(3x^2)) ?

The derivative of 1/(2x-8/(3x^2)) is -1/(2x^2)+(16)/(3x^3)

What is the first derivative of 1/(2x-8/(3x^2)) ?

The first derivative of 1/(2x-8/(3x^2)) is -1/(2x^2)+(16)/(3x^3)

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\frac{d}{d x} (\frac{1}{2 x} - \frac{8}{3 x ^{2}})

- \frac{1}{2 x ^{2}} + \frac{16}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x} - \frac{8}{3 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) - \frac{d}{d x} (\frac{8}{3 x ^{2}})

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

\frac{d}{d x} (\frac{8}{3 x ^{2}}) = - \frac{16}{3 x ^{3}}

= - \frac{1}{2 x ^{2}} - (- \frac{16}{3 x ^{3}})

Simplify

= - \frac{1}{2 x ^{2}} + \frac{16}{3 x ^{3}}

\int (x^{3} - 2 x^{2})^{3} d x

x \to 0 - lim (e^{\frac{7}{x}})

\int \frac{1}{( x + a ) ^{2}} d x

\int sin (a x) sin (b x) d x

y = x^{4} + 5 e^{x}, (0, 5)

What is the derivative of 1/(2x-8/(3x^2)) ?
The derivative of 1/(2x-8/(3x^2)) is -1/(2x^2)+(16)/(3x^3)
What is the first derivative of 1/(2x-8/(3x^2)) ?
The first derivative of 1/(2x-8/(3x^2)) is -1/(2x^2)+(16)/(3x^3)