What is the tangent of f(x)= 4/x ,(4,1) ?

The tangent of f(x)= 4/x ,(4,1) is y=-1/4 x+2

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tangent of f(x)= 4/x ,(4,1)

tangent of

f (x) = \frac{4}{x}, (4, 1)

y = - \frac{1}{4} x + 2

Solution steps

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

(4, 1) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(4, 1) : y = - \frac{1}{4} x + 2

y = - \frac{1}{4} x + 2

\int_{0}^{l n (3)} 2 (3 - x e^{x}) d x

\frac{d}{d x} (x^{4} + x^{3} + x^{2} + x + 1)

\int x 3^{x^{2}} d x

f (x) = 2 - \frac{4}{x}

\int 4 sin^{2} (2 x) d x

What is the tangent of f(x)= 4/x ,(4,1) ?
The tangent of f(x)= 4/x ,(4,1) is y=-1/4 x+2