What is the derivative of-2x^{-3} ?

The derivative of-2x^{-3} is 6/(x^4)

What is the first derivative of-2x^{-3} ?

The first derivative of-2x^{-3} is 6/(x^4)

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\frac{d}{d x} (- 2 x^{- 3})

\frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (- 2 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 (- 3 x^{- 3 - 1})

Simplify

- 2 (- 3 x^{- 3 - 1}) : \frac{6}{x ^{4}}

= \frac{6}{x ^{4}}

g^{'} (x)

\int - \frac{6}{x} d x

x \to 0 - lim (arctan (\frac{1}{x}))

\frac{\partial}{\partial x} (x^{2} + 4 y)

\int_{0}^{P} \frac{1}{M - P} d P

What is the derivative of-2x^{-3} ?
The derivative of-2x^{-3} is 6/(x^4)
What is the first derivative of-2x^{-3} ?
The first derivative of-2x^{-3} is 6/(x^4)