What is the integral of-6/x ?

The integral of-6/x is -6ln|x|+C

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integral of-6/x

\int - \frac{6}{x} d x

- 6 ln ∣ x ∣ + C

Solution steps

\int - \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= - 6 ln ∣ x ∣

Add a constant to the solution

= - 6 ln ∣ x ∣ + C

x \to 0 - lim (arctan (\frac{1}{x}))

\frac{\partial}{\partial x} (x^{2} + 4 y)

\int_{0}^{P} \frac{1}{M - P} d P

(1) (0.3)

\int_{- 1}^{1} x^{3} (1 + x^{4})^{3} d x