en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=sin(3x)

Solution

y^{^{'}} = sin (3 x)

Solution

y = - \frac{1}{3} cos (3 x) + c_{1}

Solution steps

y^{'} (x) = sin (3 x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (3 x) d x

\int sin (3 x) d x = - \frac{1}{3} cos (3 x) + c_{1}

y = - \frac{1}{3} cos (3 x) + c_{1}

Popular Examples

derivative of ln(cos(0))

\frac{d}{d x} (ln (cos (0)))

integral of (4x+6)/(x^2+4)

\int \frac{4 x + 6}{x ^{2} + 4} d x

integral of 2/(3y-4)

\int \frac{2}{3 y - 4} d y

integral from-2 to 3 of \sqrt[3]{x}

integral of x^3sqrt(x^2-2)

\int x^{3} x^{2} - 2 d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=sin(3x) ?
The solution for y^'=sin(3x) is y=-1/3 cos(3x)+c_{1}