What is the limit as x approaches 0 of (ln(x))^2 ?

The limit as x approaches 0 of (ln(x))^2 is Does not exist

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limit as x approaches 0 of (ln(x))^2

x \to 0 lim ((ln (x))^{2})

Does not exist

Solution steps

x \to 0 lim ((ln (x))^{2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((ln (x))^{2}) = \infty

x \to 0 - lim ((ln (x))^{2}) =

Does not exist

= Does not exist

x \to - 1 + lim (\frac{1}{x ^{2} + 1})

\int (6 x^{2} - 5 x - 1) d x

x \to \infty lim (\frac{i}{n})

\frac{d y}{d x} - y - \frac{y ^{2}}{4} = 0

\int (2 x + 8 x^{2}) d x

What is the limit as x approaches 0 of (ln(x))^2 ?
The limit as x approaches 0 of (ln(x))^2 is Does not exist