What is the limit as x approaches-1+of 1/(x^2+1) ?

The limit as x approaches-1+of 1/(x^2+1) is 1/2

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limit as x approaches-1+of 1/(x^2+1)

x \to - 1 + lim (\frac{1}{x ^{2} + 1})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

x \to - 1 + lim (\frac{1}{x ^{2} + 1})

Plug in the value

x = - 1

= \frac{1}{( - 1 ) ^{2} + 1}

(- 1)^{2} + 1 = 2

= \frac{1}{2}

\int (6 x^{2} - 5 x - 1) d x

x \to \infty lim (\frac{i}{n})

\frac{d y}{d x} - y - \frac{y ^{2}}{4} = 0

\int (2 x + 8 x^{2}) d x

\frac{d}{d x} (\frac{y}{x ^{2}})

What is the limit as x approaches-1+of 1/(x^2+1) ?
The limit as x approaches-1+of 1/(x^2+1) is 1/2