What is the derivative of sec^2(9x) ?

The derivative of sec^2(9x) is 18sec^2(9x)tan(9x)

What is the first derivative of sec^2(9x) ?

The first derivative of sec^2(9x) is 18sec^2(9x)tan(9x)

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\frac{d}{d x} (sec^{2} (9 x))

18 sec^{2} (9 x) tan (9 x)

Solution steps

\frac{d}{d x} (sec^{2} (9 x))

Apply the chain rule:

2 sec (9 x) \frac{d}{d x} (sec (9 x))

= 2 sec (9 x) \frac{d}{d x} (sec (9 x))

\frac{d}{d x} (sec (9 x)) = sec (9 x) tan (9 x) \cdot 9

= 2 sec (9 x) sec (9 x) tan (9 x) \cdot 9

Simplify

2 sec (9 x) sec (9 x) tan (9 x) \cdot 9 : 18 sec^{2} (9 x) tan (9 x)

= 18 sec^{2} (9 x) tan (9 x)

\frac{\partial}{\partial x} (\frac{1}{2 x} arctan (\frac{y}{x}))

\frac{8 x ^{2} + 4 x + 4}{4}

\int (e^{x} + 5) d x

x \to 3 lim (9 - x^{2})

What is the derivative of sec^2(9x) ?
The derivative of sec^2(9x) is 18sec^2(9x)tan(9x)
What is the first derivative of sec^2(9x) ?
The first derivative of sec^2(9x) is 18sec^2(9x)tan(9x)