What is the tangent of f(x)= x/(x+1),\at x=-2 ?

The tangent of f(x)= x/(x+1),\at x=-2 is y=x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= x/(x+1),\at x=-2

tangent of

f (x) = \frac{x}{x + 1}, at x = - 2

y = x + 4

Solution steps

Find the tangent point:

(- 2, 2)

Find the slope of

f (x) = \frac{x}{x + 1} : \frac{df ( x )}{d x} = \frac{1}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{x}{x + 1}

x = - 2 : m = 1

Find the line with slope m=

1

and passing through

(- 2, 2) : y = x + 4

y = x + 4

\frac{\partial}{\partial x} (- \frac{1}{2 x ^{2}})

\int 1 + \frac{1}{( x + 1 ) ^{2}} d x

\frac{d}{d x} (sin^{- 1} (x))

\int sec^{2} (X) d X

x \to - 3 - lim (\frac{3}{x ^{2} - 9})

What is the tangent of f(x)= x/(x+1),\at x=-2 ?
The tangent of f(x)= x/(x+1),\at x=-2 is y=x+4