What is the integral of ((ln(x))^2) ?

The integral of ((ln(x))^2) is xln^2(x)-2(xln(x)-x)+C

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integral of ((ln(x))^2)

\int ((ln (x))^{2}) d x

x ln^{2} (x) - 2 (x ln (x) - x) + C

Solution steps

\int (ln (x))^{2} d x

Apply Integration By Parts

: x ln^{2} (x) - \int 2 ln (x) d x

= x ln^{2} (x) - \int 2 ln (x) d x

\int 2 ln (x) d x = 2 (x ln (x) - x)

= x ln^{2} (x) - 2 (x ln (x) - x)

Add a constant to the solution

= x ln^{2} (x) - 2 (x ln (x) - x) + C

4 x^{2} tan (x)

\frac{\partial}{\partial x} (x e x p (x, y, z) (- x^{2} - y^{2} - z^{2}))

f (x) = - 4 sin (x), at x = π

\int \frac{sech ^{2} ( x )}{tanh ( x )} d x

\int_{0}^{1} (x^{2} + 5) e^{- x} d x

What is the integral of ((ln(x))^2) ?
The integral of ((ln(x))^2) is xln^2(x)-2(xln(x)-x)+C