What is the tangent of f(x)=-4sin(x),\at x=pi ?

The tangent of f(x)=-4sin(x),\at x=pi is y=4x-4pi

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tangent of f(x)=-4sin(x),\at x=pi

tangent of

f (x) = - 4 sin (x), at x = π

y = 4 x - 4 π

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

f (x) = - 4 sin (x) : \frac{df ( x )}{d x} = - 4 cos (x)

Compute the slope of

f (x) = - 4 sin (x)

x = π : m = 4

Find the line with slope m=

4

and passing through

(π, 0) : y = 4 x - 4 π

y = 4 x - 4 π

\int \frac{sech ^{2} ( x )}{tanh ( x )} d x

\int_{0}^{1} (x^{2} + 5) e^{- x} d x

\int \frac{1000}{100 x} d x

\int_{0}^{3 - x} 3 - x - y d y

\frac{d}{d x} (x tan (\frac{1}{x}))

What is the tangent of f(x)=-4sin(x),\at x=pi ?
The tangent of f(x)=-4sin(x),\at x=pi is y=4x-4pi