What is the integral from 0 to 1 of (2(x+2))/5 ?

The integral from 0 to 1 of (2(x+2))/5 is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (2(x+2))/5

\int_{0}^{1} \frac{2 ( x + 2 )}{5} d x

1

Solution steps

\int_{0}^{1} \frac{2 ( x + 2 )}{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{5} \cdot \int_{0}^{1} x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{2}{5} (\int_{0}^{1} x d x + \int_{0}^{1} 2 d x)

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 2 d x = 2

= \frac{2}{5} (\frac{1}{2} + 2)

Simplify

\frac{2}{5} (\frac{1}{2} + 2) : 1

= 1

tan (2^{x})

\frac{d}{d x} ((7 x^{2} - 11 x) e^{x})

x \to 8 - lim (\frac{2 x}{x + 8})

y^{^{'}} - \frac{1}{x} y = (1 + ln (x)) y^{3}

f (x) = 4 x^{2}

What is the integral from 0 to 1 of (2(x+2))/5 ?
The integral from 0 to 1 of (2(x+2))/5 is 1