What is the derivative of tan(2^x) ?

The derivative of tan(2^x) is sec^2(2^x)*2^xln(2)

What is the first derivative of tan(2^x) ?

The first derivative of tan(2^x) is sec^2(2^x)*2^xln(2)

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derivative of

tan (2^{x})

sec^{2} (2^{x}) \cdot 2^{x} ln (2)

Solution steps

\frac{d}{d x} (tan (2^{x}))

Apply the chain rule:

sec^{2} (2^{x}) \frac{d}{d x} (2^{x})

= sec^{2} (2^{x}) \frac{d}{d x} (2^{x})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

= sec^{2} (2^{x}) \cdot 2^{x} ln (2)

\frac{d}{d x} ((7 x^{2} - 11 x) e^{x})

x \to 8 - lim (\frac{2 x}{x + 8})

y^{^{'}} - \frac{1}{x} y = (1 + ln (x)) y^{3}

f (x) = 4 x^{2}

\frac{d}{d x} (x^{3} - x^{2} - x + 2)

What is the derivative of tan(2^x) ?
The derivative of tan(2^x) is sec^2(2^x)*2^xln(2)
What is the first derivative of tan(2^x) ?
The first derivative of tan(2^x) is sec^2(2^x)*2^xln(2)