What is the sum from n=0 to infinity of 1/(6^n) ?

The sum from n=0 to infinity of 1/(6^n) is 6/5

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sum from n=0 to infinity of 1/(6^n)

n = 0 \sum \infty \frac{1}{6 ^{n}}

\frac{6}{5}

Solution steps

n = 0 \sum \infty \frac{1}{6 ^{n}}

Apply Series Geometric Test:

\frac{6}{5}

= \frac{6}{5}

x y^{^{'}} + 2 y = 12 x^{2}

\frac{d}{d t} (sin (t^{3}))

\int \frac{x ^{3} + 3 x ^{2} - 5 x - 1}{x ^{2} - x} d x

f (x) = \frac{4}{( x ^{2} + 6 x ) ^{3}}

\int \frac{( ln ( t ) ) ^{4}}{t} d t

What is the sum from n=0 to infinity of 1/(6^n) ?
The sum from n=0 to infinity of 1/(6^n) is 6/5