What is the d/(dt)(sin(t^3)) ?

The d/(dt)(sin(t^3)) is cos(t^3)*3t^2

What is the first d/(dt)(sin(t^3)) ?

The first d/(dt)(sin(t^3)) is cos(t^3)*3t^2

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\frac{d}{d t} (sin (t^{3}))

cos (t^{3}) \cdot 3 t^{2}

Solution steps

\frac{d}{d t} (sin (t^{3}))

Apply the chain rule:

cos (t^{3}) \frac{d}{d t} (t^{3})

= cos (t^{3}) \frac{d}{d t} (t^{3})

\frac{d}{d t} (t^{3}) = 3 t^{2}

= cos (t^{3}) \cdot 3 t^{2}

\int \frac{x ^{3} + 3 x ^{2} - 5 x - 1}{x ^{2} - x} d x

f (x) = \frac{4}{( x ^{2} + 6 x ) ^{3}}

\int \frac{( ln ( t ) ) ^{4}}{t} d t

\int 2 x + c d x

\int sin (2 π x) cos (5 π x) d x

What is the d/(dt)(sin(t^3)) ?
The d/(dt)(sin(t^3)) is cos(t^3)*3t^2
What is the first d/(dt)(sin(t^3)) ?
The first d/(dt)(sin(t^3)) is cos(t^3)*3t^2