What is laplacetransform s^2-4s+3 ?

The answer to laplacetransform s^2-4s+3 is 2/(s^3)-4/(s^2)+3/s

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laplacetransform s^2-4s+3

laplace transform

s^{2} - 4 s + 3

\frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{3}{s}

Solution steps

L {s^{2} - 4 s + 3}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {s^{2}} - 4 L {s} + L {3}

L {s^{2}} : \frac{2}{s ^{3}}

L {s} : \frac{1}{s ^{2}}

L {3} : \frac{3}{s}

= \frac{2}{s ^{3}} - 4 \cdot \frac{1}{s ^{2}} + \frac{3}{s}

Refine

\frac{2}{s ^{3}} - 4 \frac{1}{s ^{2}} + \frac{3}{s} : \frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{3}{s}

= \frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{3}{s}

\int (x^{4} - 1) x^{2} d x

\frac{d y}{d x} = y (2 - 3 y)

f (x) = ln (x^{2} + 2)

\int 2 sin (x) - 3 cos (x) d x

f (x) = \frac{x ^{2}}{x + 2}, at x = 3

What is laplacetransform s^2-4s+3 ?
The answer to laplacetransform s^2-4s+3 is 2/(s^3)-4/(s^2)+3/s