What is the derivative of 2x^2+x-2 ?

The derivative of 2x^2+x-2 is 4x+1

What is the first derivative of 2x^2+x-2 ?

The first derivative of 2x^2+x-2 is 4x+1

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derivative of

2 x^{2} + x - 2

4 x + 1

Solution steps

\frac{d}{d x} (2 x^{2} + x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 4 x + 1 - 0

Simplify

= 4 x + 1

\int_{0}^{\infty} \frac{5}{x ^{3}} d x

0 = x^{2} - x y + 2 y - 2, at x = - 2

\frac{\partial}{\partial x} (x^{3} \cdot y^{2} + 4 x^{2} - 3 x y)

x \to \infty lim (x - {x})

\int 2 yz d y

What is the derivative of 2x^2+x-2 ?
The derivative of 2x^2+x-2 is 4x+1
What is the first derivative of 2x^2+x-2 ?
The first derivative of 2x^2+x-2 is 4x+1