What is the derivative of ln(x-pi/2) ?

The derivative of ln(x-pi/2) is 2/(2x-pi)

What is the first derivative of ln(x-pi/2) ?

The first derivative of ln(x-pi/2) is 2/(2x-pi)

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\frac{d}{d x} (ln (x - \frac{π}{2}))

\frac{2}{2 x - π}

Solution steps

\frac{d}{d x} (ln (x - \frac{π}{2}))

Apply the chain rule:

\frac{1}{x - \frac{π}{2}} \frac{d}{d x} (x - \frac{π}{2})

= \frac{1}{x - \frac{π}{2}} \frac{d}{d x} (x - \frac{π}{2})

\frac{d}{d x} (x - \frac{π}{2}) = 1

= \frac{1}{x - \frac{π}{2}} \cdot 1

Simplify

\frac{1}{x - \frac{π}{2}} \cdot 1 : \frac{2}{2 x - π}

= \frac{2}{2 x - π}

x \to \infty lim (42 + x)

y^{^{'}} + y = x + 5

\int \frac{1}{64 + x ^{2}} d x

\int \frac{( x ^{3} )}{1 + x ^{2}} d x

2 x^{2} + x - 2

What is the derivative of ln(x-pi/2) ?
The derivative of ln(x-pi/2) is 2/(2x-pi)
What is the first derivative of ln(x-pi/2) ?
The first derivative of ln(x-pi/2) is 2/(2x-pi)