What is the tangent of f(x)=2x^4-10x^2,\at x=-2 ?

The tangent of f(x)=2x^4-10x^2,\at x=-2 is y=-24x-56

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tangent of f(x)=2x^4-10x^2,\at x=-2

tangent of

f (x) = 2 x^{4} - 10 x^{2}, at x = - 2

y = - 24 x - 56

Solution steps

Find the tangent point:

(- 2, - 8)

Find the slope of

f (x) = 2 x^{4} - 10 x^{2} : \frac{df ( x )}{d x} = 8 x^{3} - 20 x

Compute the slope of

f (x) = 2 x^{4} - 10 x^{2}

x = - 2 : m = - 24

Find the line with slope m=

- 24

and passing through

(- 2, - 8) : y = - 24 x - 56

y = - 24 x - 56

\frac{d}{d x} (ln (x - \frac{π}{2}))

x \to \infty lim (42 + x)

y^{^{'}} + y = x + 5

\int \frac{1}{64 + x ^{2}} d x

\int \frac{( x ^{3} )}{1 + x ^{2}} d x

What is the tangent of f(x)=2x^4-10x^2,\at x=-2 ?
The tangent of f(x)=2x^4-10x^2,\at x=-2 is y=-24x-56