What is the integral from 0 to 4 of-x^2 ?

The integral from 0 to 4 of-x^2 is -64/3

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integral from 0 to 4 of-x^2

\int_{0}^{4} - x^{2} d x

- \frac{64}{3}

Decimal Notation

- 21.33333 \dots

Solution steps

\int_{0}^{4} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= - [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= - \frac{64}{3}

x \to 2 lim (4 - 2 x)

\frac{d y}{d x} - y = 3 e^{x} + 12 e^{4 x}

\int x^{2} \cdot 16 - x^{2} d x

\frac{d}{d x} (\frac{x - 15}{x - 15})

4 x + 8

What is the integral from 0 to 4 of-x^2 ?
The integral from 0 to 4 of-x^2 is -64/3