What is the derivative of sqrt(4x+8) ?

The derivative of sqrt(4x+8) is 1/(sqrt(x+2))

What is the first derivative of sqrt(4x+8) ?

The first derivative of sqrt(4x+8) is 1/(sqrt(x+2))

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derivative of

4 x + 8

\frac{1}{x + 2}

Solution steps

\frac{d}{d x} (4 x + 8)

Apply the chain rule:

\frac{1}{2 4 x + 8} \frac{d}{d x} (4 x + 8)

= \frac{1}{2 4 x + 8} \frac{d}{d x} (4 x + 8)

\frac{d}{d x} (4 x + 8) = 4

= \frac{1}{2 4 x + 8} \cdot 4

Simplify

\frac{1}{2 4 x + 8} \cdot 4 : \frac{1}{x + 2}

= \frac{1}{x + 2}

x \to 1 lim (x - 3)

y = x \cdot e^{4 - x}

y = x - 1, x - y = 1

\frac{d}{d x} ((5 x)^{4 x})

\frac{d}{d x} ((sec (sin (x^{2} + 6^{x})))^{4})

What is the derivative of sqrt(4x+8) ?
The derivative of sqrt(4x+8) is 1/(sqrt(x+2))
What is the first derivative of sqrt(4x+8) ?
The first derivative of sqrt(4x+8) is 1/(sqrt(x+2))