What is area sin(x),cos(x),x=-pi/6 ?

The answer to area sin(x),cos(x),x=-pi/6 is (1-sqrt(3))/2+3sqrt(2)

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area sin(x),cos(x),x=-pi/6

area

sin (x), cos (x), x = - \frac{π}{6}

\frac{1 - 3}{2} + 32

Decimal Notation

3.87661 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{6}}^{\frac{5 π}{4}} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{- \frac{π}{6}}^{\frac{5 π}{4}} ∣ sin (x) - cos (x) ∣ d x : \frac{1 - 3}{2} + 32

The area is:

= \frac{1 - 3}{2} + 32

\frac{d}{d x} (x^{2} e^{5 x})

7 + 4 x

\int_{0}^{4} - x^{2} d x

x \to 2 lim (4 - 2 x)

\frac{d y}{d x} - y = 3 e^{x} + 12 e^{4 x}

What is area sin(x),cos(x),x=-pi/6 ?
The answer to area sin(x),cos(x),x=-pi/6 is (1-sqrt(3))/2+3sqrt(2)