What is the derivative of (4x/(7x-2)) ?

The derivative of (4x/(7x-2)) is -8/((7x-2)^2)

What is the first derivative of (4x/(7x-2)) ?

The first derivative of (4x/(7x-2)) is -8/((7x-2)^2)

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\frac{d}{d x} (\frac{4 x}{7 x - 2})

- \frac{8}{( 7 x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{7 x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{7 x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( 7 x - 2 ) - \frac{d}{d x} ( 7 x - 2 ) x}{( 7 x - 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (7 x - 2) = 7

= 4 \cdot \frac{1 \cdot ( 7 x - 2 ) - 7 x}{( 7 x - 2 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( 7 x - 2 ) - 7 x}{( 7 x - 2 ) ^{2}} : - \frac{8}{( 7 x - 2 ) ^{2}}

= - \frac{8}{( 7 x - 2 ) ^{2}}

\frac{1}{( 2 s + 1 ) s}

\int x^{2} ln (9 x) d x

\frac{d}{d x} (\frac{tan ^{2} ( x )}{tan ( x ^{2} )})

x \frac{d y}{d x} = e^{7 y + x}

n = 1 \sum \infty 5 (- \frac{1}{6})^{5 n}

What is the derivative of (4x/(7x-2)) ?
The derivative of (4x/(7x-2)) is -8/((7x-2)^2)
What is the first derivative of (4x/(7x-2)) ?
The first derivative of (4x/(7x-2)) is -8/((7x-2)^2)