What is the sum from n=1 to infinity of 5(-1/6)^{5n} ?

The sum from n=1 to infinity of 5(-1/6)^{5n} is converges

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sum from n=1 to infinity of 5(-1/6)^{5n}

n = 1 \sum \infty 5 (- \frac{1}{6})^{5 n}

converges

Solution steps

n = 1 \sum \infty 5 (- \frac{1}{6})^{5 n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty (- \frac{1}{6})^{5 n}

Apply Series Ratio Test:

converges

= 5 converges

= converges

f (x) = \frac{2 x ^{2} - x - 1}{2 x + 2}

x \to 0 + lim (x^{20 x})

\frac{d}{d x} (7 x^{4} cot (x))

x y d x - (1 + x^{2}) d y = 0

x^{''}

What is the sum from n=1 to infinity of 5(-1/6)^{5n} ?
The sum from n=1 to infinity of 5(-1/6)^{5n} is converges