What is the derivative of 2ln(x^2) ?

The derivative of 2ln(x^2) is 4/x

What is the first derivative of 2ln(x^2) ?

The first derivative of 2ln(x^2) is 4/x

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\frac{d}{d x} (2 ln (x^{2}))

\frac{4}{x}

Solution steps

\frac{d}{d x} (2 ln (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (x^{2}))

Apply the chain rule:

\frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

= \frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 2 \cdot \frac{1}{x ^{2}} \cdot 2 x

Simplify

2 \cdot \frac{1}{x ^{2}} \cdot 2 x : \frac{4}{x}

= \frac{4}{x}

n = 1 \sum \infty 1 0^{n} x^{n}

\int (x^{2} + 5 x + 6) cos (2 x) d x

y = x, g (y, x) = x^{2}, [0, 1]

\frac{d}{d x} (cos (sin^{3} (5 x - 5)))

y^{^{'}} = \frac{( y ^{3} + 1 )}{( 3 x y ^{2} )}

What is the derivative of 2ln(x^2) ?
The derivative of 2ln(x^2) is 4/x
What is the first derivative of 2ln(x^2) ?
The first derivative of 2ln(x^2) is 4/x