What is the derivative of f(x)=4x^{-2} ?

The derivative of f(x)=4x^{-2} is -8/(x^3)

What is the first derivative of f(x)=4x^{-2} ?

The first derivative of f(x)=4x^{-2} is -8/(x^3)

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derivative of

f (x) = 4 x^{- 2}

- \frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (4 x^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 2 x^{- 2 - 1})

Simplify

4 (- 2 x^{- 2 - 1}) : - \frac{8}{x ^{3}}

= - \frac{8}{x ^{3}}

\int \frac{3}{4} - x^{2} d x

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\int \frac{2 x + 2}{x ^{2} + 1} d x

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What is the derivative of f(x)=4x^{-2} ?
The derivative of f(x)=4x^{-2} is -8/(x^3)
What is the first derivative of f(x)=4x^{-2} ?
The first derivative of f(x)=4x^{-2} is -8/(x^3)